26' 2 axle box truck GVWR is less than the sum of the GAWRs? Am I overweight?

Discussion in 'Ask An Owner Operator' started by bakelk, Feb 7, 2024.

  1. bakelk

    bakelk Bobtail Member

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    Feb 7, 2024
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    The truck has a GVWR of 19,500. The combined GAWRs are 25,500. The maximum payload we work with is ~16,000 and the empty GVW is 12,000 (a lift was installed after registration and we estimate that now the empty GVW is 15,000).

    In Colorado, the Single Vehicle Weight w/2 axles is 36,000.
     
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  3. Cowboyrich

    Cowboyrich Road Train Member

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    I would ask CO state patrol or take empty truck to a scale and ask them, that's the best way (in my opinion) to get a definite yes or no answer.
     
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  4. Pepper24

    Pepper24 Road Train Member

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    You should be fine .You didn’t mention what gross weight you registered the truck to haul.The GVWR is the max payload you can safely load.The GAWR is the max axle rate.You would want to load the truck then scale the front and back axles and see where you’re at you should be fine with a 16,000 lbs load
     
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  5. Bean Jr.

    Bean Jr. Road Train Member

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    He said the GVWR is 19,500. If its tare weight is 12,000 and the load is 16,000, that sounds like he's way over!
     
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  6. Bean Jr.

    Bean Jr. Road Train Member

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    GVWR is including the truck. Sounds like a typo or something.
     
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  7. SmallPackage

    SmallPackage Road Train Member

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    What are you registered for? If the truck is only rated for 19,500 gvw then you are way over on rating. You at 15,000 empty weight you can only legally carry 4,500 lbs.

    We ran 24’ single axle straight trucks with lift gates that were built as 33,000 GVWR but registered for 26,000. Two identical “bookend” trucks. One weighed 15,000 empty the other was 11,000. We were always over legal for licensing but not truck rating.
     
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  8. rbrtwbstr

    rbrtwbstr Road Train Member

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    Sounds like you can only legally haul 4500 lbs. The GVWR is the highest weight you can register for, unless towing a trailer then it goes by GCVWR. (at least in PA anyways)
     
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  9. Pepper24

    Pepper24 Road Train Member

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    Maybe i I’m missing something isn’t the GVWR is payload rating of a vehicle it’s no the net weight of the vehicle..For example a pneumatic tank the gvwr is usually around 60,000 lbs I don’t think there’s a company that can scale it but the trailer has the capability of loading 60,000 lbs that not the trailer weight it’s how much payload the trailer is rated to load
     
    Last edited: Feb 9, 2024
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  10. LTL Bull

    LTL Bull Road Train Member

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    The gross vehicle weight rating (GVWR), or gross vehicle mass (GVM), is the maximum operating weight/mass of a vehicle as specified by the manufacturer[6] including the vehicle's chassis, body, engine, engine fluids, fuel, accessories, driver, passengers and cargo but excluding that of any trailers.[7]

    The weight of a vehicle is influenced by passengers, cargo, even fuel level, so a number of terms are used to express the weight of a vehicle in a designated state. Gross combined weight rating (GCWR) refers to the total mass of a vehicle including all trailers. GVWR and GCWR are used to specify weight limitations and restrictions. Gross trailer weight rating specifies the maximum weight of a trailer and the gross axle weight rating specifies the maximum weight on any particular axle.
     
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  11. bakelk

    bakelk Bobtail Member

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    Feb 7, 2024
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    It's a '03 Freightliner M2 106 Medium Duty with a 6.4L L6 Diesel

    I think that 16K lbs in this truck is significantly overweight, but I can't find any law that refers to the manufacturers specifications. I found the statutes below regarding loads, axles, and gross weights, but we're not in violation of them. Can a state trooper issue a citation for loading over the GVWR manufacturer's specifications?

    "CRS 42-4-507 (2)(b). Wheel and axle loads." - Gross weight upon any single axle with pneumatic tires cannot exceed 20,000 lbs.
    "CRS 42-4-508 (1)(b). Gross weight of vehicles and loads - definition." Maximum gross weight cannot exceed the weight determined by the formula
    W = 1,000 (L + 40) where L is ft between axles.
    1,000 (9.33 ft + 40) = 1,000 + 9.33 = 49,333 lbs
     
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